Consider two stationary point charges q1 = +1 nC and q2 = -2 nC separated by a distance d = 10 cm as shown in the figure below. What is the magnitude of the net electric field at point P shown in the figure below? Take k = 9 x 10^9 N.m^2/C^2.
Added by Kelly T.
Step 1
We can use Coulomb's law to do this: Electric field due to q1 at P: E1 = ke * q1 / r1^2, where r1 is the distance between q1 and P. In this case, r1 = d = 10 cm. E1 = 9 * 10^9 * 1 * 10^-9 / (10 * 10^-2)^2 = 9 * 10^3 N/C Electric field due to q2 at P: E2 = ke * Show more…
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