00:01
So, p of a is given to us as 0 .3 and p of b is given to us as 0 .3 and p of c is given to us as 0 .3.
00:12
So first, p of a union b will be equals to p of a multiplied by p of b which will be equal to 0 .3 multiplied by 0 .3 which is equals to 0 .09.
00:32
Now on to the second part, p of a union b union c which will be equal to 0 .3 multiplied by 0 .3 multiplied by 0 .3 which is equals to 0 .027.
00:51
So this is the answer for b part or we can say second part.
00:55
Now on to third part, p of a union b will be equals to p of a plus p of b minus p of a intersection b which will be equals to 0 .3 plus 0 .3 minus 0 .09 which will calculate it comes out to be 0 .51.
01:19
Now on to the fourth part, p of a union b union c will be equals to p of a plus p of b plus p of c minus p of a p of b minus p of b p of c minus p of a p of c and then plus p of a union, sorry a intersection b intersection c.
02:02
So we'll substitute in the values and we'll get the answer as 0 .657 which will be the answer for part 4.
02:11
Now moving on to part 5, we have p of a intersection b union c.
02:22
So we calculate this by p of a intersection b union probability of a intersection c which will be equal to 0 .3 multiplied by 0 .3 plus 0 .3 multiplied by 0 .3 which will be equal to 0 .18.
02:47
So this is the answer for part 5...