00:01
In the given question, side length of square field is given as 20 m and it takes t is equal to 80 seconds to cover the whole field.
00:09
We have to find out displacement at the end of 200 seconds, displacement and also velocity.
00:19
First we will find out the perimeter of square field.
00:22
The perimeter of square field is equal to 4 into 20 that is equal to 80 m.
00:30
So speed will be equal to distance upon time that is 80 m upon 80 seconds.
00:38
So speed is 1 m per second.
00:42
So the distance travelled in 200 seconds, distance is equal to speed into time.
00:51
By substituting the values we get 1 into 200.
00:56
So distance travelled in 200 seconds is 200 m.
01:01
So the number of rounds covered by the girl is equal to 200 upon 80 and this comes out to be 2 .5.
01:13
So the girl has covered 2 complete rounds and one half round.
01:27
Consider this square as square field.
01:30
Name it as abcd.
01:36
So the last one half round is from abc.
01:42
The displacement while travelling in path abc is distance from a to c.
01:55
That is the diagonal of square...