8. The cutoff wavelength for a metal is 325.6 nm. It is illuminated with light of wavelength 259.8 nm. What is the stopping potential for the photoelectrons?
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6 \) nm. Plugging in the values, we get: \( \text{Work Function} = \frac{1340}{325.6} = 4.11 \) eV. Show more…
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