00:01
In this question, there are given two samples.
00:03
Let me just take notes.
00:04
So the sample 1 and the sample 2.
00:06
For the sample 1, the x1 value is 371 and the sample size 532.
00:12
And for the second one, the x2 is 433 and the sample size which is 558 and the confidence level which is given as 90 % which is 0 .9.
00:25
So first of all, let's get the proportion value.
00:28
So the proportion is equal to x over n.
00:30
So for the first sample size, let's say the proportion value is p1 which is x1 over n1.
00:39
371, 532.
00:42
371 divided by 532.
00:47
So the value with, this is three decimal places.
00:51
Let me just take three decimal places.
00:53
This is 6, 9 and 7.
00:56
Let's get the second proportion value which is x2 over n2.
01:00
This is 433 divided by 558.
01:04
433 divided by 558.
01:07
So the value is 0 .77 and 6.
01:10
So we have to find the confidence interval for the difference...