Cont. at 0.07.0°. 2011 a) What is the wavelength of the incident light? b) If the screen on which the diffraction pattern is produced is placed 0.8m away from the slit, determine the width of the central maximum.
Added by Mohamed M.
Step 1
Step 1: We can use the formula for the angle of the first minimum in a single-slit diffraction pattern: sin(θ) = mλ/d, where θ is the angle, λ is the wavelength, d is the width of the slit, and m is the order of the minimum (in this case, m = 1 for the first Show more…
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Light with a wavelength of $587.5 \mathrm{~nm}$ illuminates a single slit $0.750 \mathrm{~mm}$ in width. (a) At what distance from the slit should a screen be located if the first minimum in the diffraction pattern is to be $0.850 \mathrm{~mm}$ from the center of the screen? (b) What is the width of the central maximum?
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