Convert the following system into triangular form and then use back-substitution to solve the system. \[ \left\{\begin{array}{rr} 3 x+3 y+3 z= & 5 \\ 7 x-6 y= & 28 \\ 3 z= & -1 \end{array}\right. \] The solution set is \( \{(\square, \square, \square)\} \). (Simplify your answers.)
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The given system of equations is: \[ \left\{\begin{array}{rr} 3 x+3 y+3 z= & 5 \\ 7 x-6 y= & 28 \\ 3 z= & -1 \end{array}\right. \] Show more…
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