Convolution: Exercise #1 • Find the convolution of the two signals $x_1(t) = 2u(t) - 2u(t - 1)$ $x_2(t) = u(t - 1) - u(t - 3)$
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Step 1: The convolution of two signals $x_1(t)$ and $x_2(t)$ is defined as: $y(t) = x_1(t) * x_2(t) = \int_{-\infty}^{\infty} x_1(\tau)x_2(t - \tau) d\tau$ In this case, we have: $x_1(t) = 2u(t) - 2u(t - 1)$ $x_2(t) = u(t - 1) - u(t - 3)$ Show more…
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