00:01
To calculate the molar solubility and the gram solubility, first we will write down the reaction which is going to happen.
00:06
So here we have a silver arsenate molecule that is ag3 aso4, ag3 s .o4.
00:12
In this, it decomposes to give 3ag plus plus aso4 3 minus.
00:20
So this is a quesform.
00:22
This is a quest form and this is a solid.
00:25
Okay.
00:26
Now in this case, what happens over here? so since we let's suppose we have the solubility as s.
00:34
So this becomes what? it will become 3s and this becomes s.
00:39
So here it will imply that the solubility product ksp will be equal to 3s, the whole cube multiplied by s.
00:48
Right? so this becomes 27s raised to 4.
00:55
So the ksp value is given to us that is 1 into 10 to minus 22.
00:59
1 into 10.
01:00
Minus 22.
01:02
So from this, we can calculate the molar solubility, that means s value.
01:06
Molar solubility, that means s value, which will be equal to fourth root of, fourth under root of 1 into 10 to the power of minus 22 divided by 27.
01:22
Right? so this is covering everything.
01:26
It is like the whole one.
01:30
Here we have 27.
01:31
So once we do this, this comes out to be equal to...