Question

Corn. The average yield of corn (bushels per acre) for Iowa counties during 2018 can be described by a Normal distribution with a mean of 192.6 bushels per acre and a standard deviation of 20.3 bushels per acre. Use the 68-95-99.7 Rule (Empirical Rule) to answer the following questions. (a) Create a well labeled normal curve for the average corn yield (bushels per acre) for Iowa counties during 2018. On this graph numerically label the mean (iv), the center 68% (iii) and (v), the center 95% (ii) and (vi) and the center 99.7% (i) and (vii). Report answers (i) through (vii.) in Canvas. You should also use this picture to help you answer the next few questions. (b) The middle 95% of counties have a corn yield between what two values? c) What is the value of the 84th percentile of corn yield for counties in Iowa? (d) What proportion of counties have a corn yield between 152.0 and 212.9 bushels per acre? (e) 0.15% of counties have a corn yield more than or equal to what value? (f) What proportion of counties have a corn yield of at most 233.2 bushels per acre? 

          Corn. The average yield of corn (bushels per acre) for Iowa
counties during 2018 can be described by a Normal distribution with
a mean of 192.6 bushels per acre and a standard deviation of 20.3
bushels per acre. Use the 68-95-99.7 Rule (Empirical Rule) to
answer the following questions.
(a) Create a well labeled normal curve for the average corn yield
(bushels per acre) for Iowa counties during 2018. On this graph
numerically label the mean (iv), the center 68% (iii) and (v), the
center 95% (ii) and (vi) and the center 99.7% (i) and (vii). Report
answers (i) through (vii.) in Canvas. You should also use this
picture to help you answer the next few questions.
(b) The middle 95% of counties have a corn yield between what two
values?
c) What is the value of the 84th percentile of corn yield for
counties in Iowa?
(d) What proportion of counties have a corn yield between 152.0 and
212.9 bushels per acre?
(e) 0.15% of counties have a corn yield more than or equal to what
value?
(f) What proportion of counties have a corn yield of at most 233.2
bushels per acre?
Show more…

Added by Jaime C.

Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Corn. The average yield of corn (bushels per acre) for Iowa counties during 2018 can be described by a Normal distribution with a mean of 192.6 bushels per acre and a standard deviation of 20.3 bushels per acre. Use the 68-95-99.7 Rule (Empirical Rule) to answer the following questions. (a) Create a well labeled normal curve for the average corn yield (bushels per acre) for Iowa counties during 2018. On this graph numerically label the mean (iv), the center 68% (iii) and (v), the center 95% (ii) and (vi) and the center 99.7% (i) and (vii). Report answers (i) through (vii.) in Canvas. You should also use this picture to help you answer the next few questions. (b) The middle 95% of counties have a corn yield between what two values? c) What is the value of the 84th percentile of corn yield for counties in Iowa? (d) What proportion of counties have a corn yield between 152.0 and 212.9 bushels per acre? (e) 0.15% of counties have a corn yield more than or equal to what value? (f) What proportion of counties have a corn yield of at most 233.2 bushels per acre?
Close icon
Play audio
Feedback
Powered by NumerAI
Danielle Fairburn Kathleen Carty
Jennifer Stoner verified

Sheryl Ezze and 91 other subject Intro Stats / AP Statistics educators are ready to help you.

Ask a new question
*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs
*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.
*

Recommended Videos

-
corn-corn-yield-in-lowa-was-historically-low-in-2012-for-all-ia-counties-the-yield-of-corn-bushels-per-acre-during-2012-follows-bell-shaped-distribution-symmetric-and-unimodal-with-a-mean-of-81355

Corn: Corn yield in Iowa was historically low in 2012. For all IA counties, the yield of corn (bushels per acre) during 2012 follows a bell-shaped distribution (symmetric and unimodal) with a mean of 299 bushels per acre and a standard deviation of 33 bushels per acre. Use the 68-95-99.7 Rule (Empirical Rule) to answer the following question: 0.15% of counties have corn yield more than or equal to what value?

Joanna Q.
question-4-14-during-a-particular-year-the-corn-yield-per-bushel-was-recorded-for-180-corn-growing-fieldsthe-output-shown-below-was-obtained-from-excel-calculations-41-a-farmerwho-does-not-k-14074

QUESTION 4 [14] During a particular year, the corn yield per bushel was recorded for 180 corn-growing fields. The output shown below was obtained from Excel calculations. 4.1 A farmer who does not know how to read statistical results asks you to explain the meaning of the information in the dot plot, mean, standard deviation, and skewness. (4) 4.2 Assuming that the data are normally distributed, between which values will the central 95% of the yields be? (2) Dot plot of corn yield: 18 16 14 15 10 150 160 170 180 190 200 Mean Standard Deviation Skewness: 172.983 7.285 0.634 4.3 A frequency distribution of corn yield values is shown in the table below. Calculate the midpoints for each of the classes and use this information together with the frequencies to calculate the mean and variance of the yields. (8) Lower Upper Frequency 155.5 160.5 6 160.5 165.5 17 165.5 170.5 54 170.5 175.5 48 175.5 180.5 28 180.5 185.5 16 185.5 190.5 6 190.5 195.5 5 180

Adi S.
in-an-agricultural-study-the-average-amount-of-corn-yield-is-normally-distributed-with-a-mean-of-1852-bushels-of-corn-per-acre-with-a-standard-deviation-of-235-bushels-of-corn-if-a-study-inc-52627

In an agricultural study, the average amount of corn yield is normally distributed with a mean of 185.2 bushels of corn per acre, with a standard deviation of 23.5 bushels of corn. If a study included 1100 acres, about how many would be expected to yield more than 190 bushels of corn per acre?

Ahmet Y.
*

Recommended Textbooks

-
Elementary Statistics a Step by Step Approach

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition
achievement 1,005 solutions
The Practice of Statistics for AP

The Practice of Statistics for AP

Daren S. Starnes, Daniel S. Yates, David S. Moore 4th Edition
achievement 1,530 solutions
Introductory Statistics

Introductory Statistics

Barbara Illowsky, Susan Dean 1st Edition
achievement 1,794 solutions
*

Transcript

-
00:01 So jake, you have a normal distribution for the iowa counties in 2018 and the number of bushels of corn that are yielded.
00:12 And we have a mean and a standard deviation.
00:16 So i centered my distribution at the mean and went out one standard deviation, two standard deviations, three standard deviations in each direction by just taking the mean and adding on 20 .3 altitude of time and subtracting it away.
00:30 Now we want to find what values will be the middle 95.
00:35 That is two standard deviations away.
00:38 So that will be between these values.
00:41 So the middle 50 will be from 152 .0 to 233 .2 acres.
00:51 Excuse me, bushels per acre.
00:53 Now next we want to find the 84th percentile.
00:57 Well, we know that we have six.
01:00 68 % are in this region, this region right here.
01:05 And so 100 minus 68 is 32.
01:11 And dividing that by 2 gives us 16.
01:14 So down here is 16 % of the data.
01:18 So adding these two gives us 84%.
01:22 So the 84th percentile will be the number 212 .9 bushels per acre.
01:30 Next, we want to find what proportion are between 152 and 20012 .9.
01:40 So let's look at that.
01:43 We know that from here to here is 95%.
01:50 And so if we take 95 minus 68, we end up getting 27.
01:58 Dividing that by 2 gives us 13 .5.
02:02 So this region in here is about 13 .5 % and this is about 13 .5%.
02:09 So if we want the region from 152 to 219, we want that 13 .5 % plus the 68.
02:26 And so that's going to give us 81 .5%.
02:31 And if i just did my math right, bring the five down, these add to 11, carry the one, 81 .5%.
02:39 Now, we also want to know what value has 0 .15 % higher than what value.
02:49 And we know that for the, let's see what color we haven't used blue, we know if we go out three standard deviations that this region between is that 99 .7%.
03:02 So we're missing 0 .3%...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade

Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever