Incorrect Question 8 0 / 2 pts What is $\Delta G^\circ$ for a cell consisting of Zn(s) in Zn(NO$_3$)$_2$(aq) and Ni(s) in Ni(NO$_3$)$_2$(aq)? -201 kJ -92.6 kJ -46.3 kJ none of these Remember, $\Delta G^\circ = -nFE^\circ$
Added by Sonya N.
Close
Step 1
The cell reaction can be written as: Zn(s) + Ni2+(aq) -> Zn2+(aq) + Ni(s) Show more…
Show all steps
Your feedback will help us improve your experience
David Collins and 71 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
What is ΔG° for a cell consisting of Zn(s) in Zn(NO3)2(aq) and Ni(s) in Ni(NO3)2(aq)? -201 kJ -92.6 kJ -46.3 kJ none of these
David C.
QUESTION 4 Given: Zn(s) + Sn2+ (aq) → Sn(s) + Zn2+ (aq) E° cell = +0.62 V What is ΔG° for this reaction at 298 K? 65.0 kJ/mol 21.2 kJ/mol -1.2 x 10^2 kJ/mol 1.2 x 10^2 kJ/mol -65.0 kJ/mol
Supreeta N.
Calculate $\Delta H_{298}^{\circ}$ for the process $\mathrm{Zn}(s)+\mathrm{S}(s)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{ZnSO}_{4}(s)$ from the following information: $$\begin{array}{l}{\mathrm{Zn}(s)+\mathrm{S}(s) \longrightarrow \mathrm{ZnS}(s) \quad \Delta H_{298}^{\circ}=-206.0 \mathrm{kJ}} \\ {\mathrm{ZnS}(s)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{ZnSO}_{4}(s) \quad \Delta H_{298}^{\circ}=-776.8 \mathrm{kJ}}\end{array}$$
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD