Question

Cost per serving (in cents) for 15 high-fiber cereals rated very good or good by a magazine for consumers are shown below. 45 49 62 41 18 77 71 30 53 53 67 43 48 27 54 Calculate the mean and standard deviation for this data set (in cents). (Round the standard deviation to one decimal place.) mean cents standard deviation cents Interpret the mean and standard deviation for this data set. The mean is the typical ---Select--- (in cents) for 15 high-fiber cereals rated very good or good by a magazine for consumers while the standard deviation is how much on average the ---Select--- deviate from the ---Select--- . The mean playing time for a large collection of compact discs is 33 minutes, and the standard deviation is 6 minutes. (a) What value (in minutes) is 1 standard deviation above the mean? One standard deviation below the mean? What values are 2 standard deviations away from the mean? 1 standard deviation above the mean min 1 standard deviation below the mean min 2 standard deviations above the mean min 2 standard deviations below the mean min (b) Assuming that the distribution of times is mound shaped and approximately symmetric, approximately what percentage of times are between 21 and 45 minutes? (Hint: See Example 3.19. Use the Empirical Rule.) % Less than 15 min or greater than 51 min? % Less than 15 min? %

          Cost per serving (in cents) for 15 high-fiber cereals rated very good or good by a magazine for consumers are shown below.

45 49 62 41 18 77 71 30 53 53 67 43 48 27 54

Calculate the mean and standard deviation for this data set (in cents). (Round the standard deviation to one decimal place.)
mean cents
standard deviation cents

Interpret the mean and standard deviation for this data set.
The mean is the typical ---Select--- (in cents) for 15 high-fiber cereals rated very good or good by a magazine for consumers while the standard deviation is how much on average the ---Select--- deviate from the ---Select--- .

The mean playing time for a large collection of compact discs is 33 minutes, and the standard deviation is 6 minutes.
(a) What value (in minutes) is 1 standard deviation above the mean? One standard deviation below the mean? What values are 2 standard deviations away from the mean?
1 standard deviation above the mean min
1 standard deviation below the mean min
2 standard deviations above the mean min
2 standard deviations below the mean min

(b) Assuming that the distribution of times is mound shaped and approximately symmetric, approximately what percentage of times are between 21 and 45 minutes? (Hint: See Example 3.19. Use the Empirical Rule.)
%
Less than 15 min or greater than 51 min?
%
Less than 15 min?
%

Cost per serving (in cents) for 15 high-fiber cereals rated very good or good by a magazine for consumers are shown below.

45 49 62 41 18 77 71 30 53 53 67 43 48 27 54

Calculate the mean and standard deviation for this data set (in cents). (Round the standard deviation to one decimal place.)
mean cents
standard deviation cents

Interpret the mean and standard deviation for this data set.
The mean is the typical —Select— (in cents) for 15 high-fiber cereals rated very good or good by a magazine for consumers while the standard deviation is how much on average the —Select— deviate from the —Select— .

The mean playing time for a large collection of compact discs is 33 minutes, and the standard deviation is 6 minutes.
(a) What value (in minutes) is 1 standard deviation above the mean? One standard deviation below the mean? What values are 2 standard deviations away from the mean?
1 standard deviation above the mean min
1 standard deviation below the mean min
2 standard deviations above the mean min
2 standard deviations below the mean min

(b) Assuming that the distribution of times is mound shaped and approximately symmetric, approximately what percentage of times are between 21 and 45 minutes? (Hint: See Example 3.19. Use the Empirical Rule.)
%
Less than 15 min or greater than 51 min?
%
Less than 15 min?
%

Added by Juan Jos- B.

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