00:01
Compound given to us is a five -member ring and there are bonds here with halbons and a chlorine.
00:08
Now this is reacting with another reactant which is having oh group and a double bond.
00:17
Now for this the first step of the mechanism will be the chlorine will leave and the second step will be the oxygen will attack as a nucleophile.
00:28
Now, why are we saying the chlorine will live? because when chlorine leaves the resultant product will have a carbocatin at this position.
00:39
And this is a territory carbocatian.
00:42
And we know that in this stability of this, territory is greater than secondary is greater than primary.
00:50
That is why this carbocatin will be stable enough.
00:53
And then we see it going to the second step where it reacts with the second.
00:58
The loan pair on the oxygen and this will attack this carbon.
01:03
Next that will be forming a compound where oh will have a positive charge and this will remain same and here there will be a methyl.
01:15
Now this is the second intermediate and finally in we see that this h is also removed and oxygen will get its charge back...