00:01
Hi, we have given matrix a equal to matrix minus 1, minus 3, 8, minus 3, 23, 1, 3 minus 7.
00:18
We need to find a inverse.
00:20
A inverse equal to adjoint of a by determinant of a.
00:26
First we can find the determinant.
00:29
Determinant of a equal to minus 1 into 70 minus 69 plus 3 into 21 minus 23 plus 8 into minus 9 plus 10, that is minus 1 minus 6 plus 8, that is 1.
00:55
So, a inverse equal to adjoined of a by 1, that is a inverse equal to adjoined of a.
01:04
I mean, know that adjoint of a is the transpose of the co -factor matrix.
01:15
So in order to find the co -factor, first we need to find the minus.
01:20
So minor is denoted by small m.
01:23
So m -1 -1 is 1.
01:25
M -1 -2 is minus 2.
01:29
M13, sorry, small m13 equal to 1.
01:32
You know how to calculate the minor right? m11 deleting this row and this column and multiplying, finding the determinant of this 2 by 2 matrix, that will be m11.
01:46
M12 deleting this column and row, then find matrix 3 minus 3 into 7 minus 1 into 23 like that.
01:56
Okay.
01:58
Then m2 .1 equal to 21 minus 24, that is minus 3.
02:04
M22 equal to minus 1.
02:07
M23 equal to 0.
02:11
M31 equal to 1.
02:13
M32 is minus 23 plus 24.
02:17
That is 1...