Question

1 Answer the following questions for the transformer below: a. What is the turns ratio of the transformer ($a$)? b. What is the voltage on the secondary side ($\bar{E}_{sec}$) if the source voltage is $\bar{E}_g = 3V\angle 40^\circ$? c. What is the current on the secondary side ($\bar{I}_{sec}$) if the source voltage is $\bar{E}_g = 3V\angle 40^\circ$? $\bar{I}_{pri}$ 1:5 $\bar{I}_{sec}$ + + + + $\bar{E}_g$ $\bar{E}_{pri}$ $\bar{E}_{sec}$ $\bar{V}_L$ $ \bar{Z}_L = 6\Omega \angle -15^\circ$

          1 Answer the following questions for the transformer below:
a. What is the turns ratio of the transformer ($a$)?
b. What is the voltage on the secondary side ($\bar{E}_{sec}$) if the source voltage is $\bar{E}_g = 3V\angle 40^\circ$?
c. What is the current on the secondary side ($\bar{I}_{sec}$) if the source voltage is $\bar{E}_g = 3V\angle 40^\circ$?
$\bar{I}_{pri}$ 1:5 $\bar{I}_{sec}$
+ + +
+ 
$\bar{E}_g$ $\bar{E}_{pri}$ $\bar{E}_{sec}$ $\bar{V}_L$
$ \bar{Z}_L = 6\Omega \angle -15^\circ$

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1 Answer the following questions for the transformer below:
a. What is the turns ratio of the transformer (a)?
b. What is the voltage on the secondary side (E̅sec) if the source voltage is E̅g = 3V∠ 40^∘?
c. What is the current on the secondary side (I̅sec) if the source voltage is E̅g = 3V∠ 40^∘?
I̅pri 1:5 I̅sec
+ + +
+
E̅g E̅pri E̅sec V̅L
Z̅L = 6Ω∠ -15^∘

Added by Craig S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

09/03/2020

Step 1

Step 1: Determine the turns ratio of the transformer The turns ratio of the transformer is given as 1:5, which means that for every 1 turn on the primary side, there are 5 turns on the secondary side. Show more…

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Could you please do clear details on how to do this, I am very confused on where to start. Answer the following guestions for the transformer below a. What is the turns ratio of the transformera)? b. What is the voltage on the secondary side (Esec) if the source voltage is Eg = 3V40? c. What is the current on the secondary side (Isec) if the source voltage is Ea = 3V40? 1pri 1sec 1 :5 Esec VL Z=6-15

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