Question

PARTICIPATION ACTIVITY 6.2.6: Handling multiple exceptions: vending machine example. Full screen The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item, and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item 2". Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non- integer input, the program throws an InputMismatchException, outputs "Fatal error", and then exits. Not all lines are used in the solution. How to use this tool Unused askForInput = true; askForInput = false; System.out.println("Fatal error"); System.out.println(excpt); catch (Exception excpt) { System.out.println(excpt.toString()); System.out.println(excpt.getMessage()); catch (InputMismatchException excpt) { } } Vending Machine.java import java.util.Scanner; import java.util.InputMismatchException; public class Vending Machine { Load default template... public static void main (String[] args) { Scanner scnr = new Scanner(System.in); int itemNumber = 0; boolean askForInput = true; while (askForInput) { try { itemNumber = scnr.nextInt(); if ((itemNumber <= 0) || (itemNumber > 8)) { } throw new Exception("Try again"); System.out.println("Dispensing item " + itemNumbe askForInput = false; Check Feedback?

          PARTICIPATION
ACTIVITY
6.2.6: Handling multiple exceptions: vending machine example.
Full screen
The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item,
and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item
2".
Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program
throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non-
integer input, the program throws an InputMismatchException, outputs "Fatal error", and then exits.
Not all lines are used in the solution.
How to use this tool
Unused
askForInput = true;
askForInput = false;
System.out.println("Fatal error");
System.out.println(excpt);
catch (Exception excpt) {
System.out.println(excpt.toString());
System.out.println(excpt.getMessage());
catch (InputMismatchException excpt) {
}
}
Vending Machine.java
import java.util.Scanner;
import java.util.InputMismatchException;
public class Vending Machine {
Load default template...
public static void main (String[] args) {
Scanner scnr = new Scanner(System.in);
int itemNumber = 0;
boolean askForInput = true;
while (askForInput) {
try {
itemNumber = scnr.nextInt();
if ((itemNumber <= 0) || (itemNumber > 8)) {
}
throw new Exception("Try again");
System.out.println("Dispensing item " + itemNumbe
askForInput = false;
Check
Feedback?

PARTICIPATION
ACTIVITY
6.2.6: Handling multiple exceptions: vending machine example.
Full screen
The following program simulates a vending machine panel. The program gets an integer that represents the user's selected item,
and then outputs a dispensing message. Only 8 items are for purchase. Ex: The input 2 results in the message "Dispensing item
2".
Arrange the following lines to handle two exceptions. If the user enters an item number that is not for purchase, the program
throws an Exception with the message "Try again", outputs the exception message, and then tries again. If the user enters a non-
integer input, the program throws an InputMismatchException, outputs "Fatal error", and then exits.
Not all lines are used in the solution.
How to use this tool
Unused
askForInput = true;
askForInput = false;
System.out.println("Fatal error");
System.out.println(excpt);
catch (Exception excpt)
System.out.println(excpt.toString());
System.out.println(excpt.getMessage());
catch (InputMismatchException excpt)

Vending Machine.java
import java.util.Scanner;
import java.util.InputMismatchException;
public class Vending Machine
Load default template...
public static void main (String[] args)
Scanner scnr = new Scanner(System.in);
int itemNumber = 0;
boolean askForInput = true;
while (askForInput)
try
itemNumber = scnr.nextInt();
if ((itemNumber <= 0) || (itemNumber > 8))

throw new Exception("Try again");
System.out.println("Dispensing item " + itemNumbe
askForInput = false;
Check
Feedback?

Added by Patricia M.

Question

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