Question

Course Home <HW#7: Ch14-S25 Problem 14.56 - Enhanced - with Feedback Part A For the elementary process $N_2O_5(g) \rightarrow N_2(g) + NO_3(g)$ the activation energy ($E_a$) and overall $\Delta E$ are 154 and 136 kJ/mol, respectively. What is the activation energy for the reverse reaction? Express your answer in kilojoules per mole using two significant figures. $E_a$(reverse) = ? kJ/mol

Name: course home hw7 ch14 s25 problem 1456 enhanced with feedback part a for the elementary process n2o5g rightarrow n2g no3g the activation energy ea and overall delta e are 154 and 136 kjm 20566
Uploaded: 2023-03-07T00:12:44-08:00
Duration: 1 min 36 s
Channel: David Collins
Description: course home hw7 ch14 s25 problem 1456 enhanced with feedback part a for the elementary process n2o5g rightarrow n2g no3g the activation energy ea and overall delta e are 154 and 136 kjm 20566

          Course Home
<HW#7: Ch14-S25
Problem 14.56 - Enhanced - with Feedback

Part A

For the elementary process
$N_2O_5(g) \rightarrow N_2(g) + NO_3(g)$
the activation energy ($E_a$) and overall $\Delta E$ are 154 and 136 kJ/mol, respectively.

What is the activation energy for the reverse reaction?
Express your answer in kilojoules per mole using two significant figures.

$E_a$(reverse) = ? kJ/mol

course home hw7 ch14 s25 problem 1456 enhanced with feedback part a for the elementary process n2o5g rightarrow n2g no3g the activation energy ea and overall delta e are 154 and 136 kjm 20566

Added by Clara H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

03/07/2023

Step 1

The relationship between the activation energies and the overall change in energy is: $\Delta E = E_a$(forward) - $E_a$(reverse) We can rearrange this equation to solve for $E_a$(reverse): $E_a$(reverse) = $E_a$(forward) - $\Delta E$ Show more…

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Course Home <HW#7: Ch14-S25 Problem 14.56 - Enhanced - with Feedback Part A For the elementary process $N_2O_5(g) \rightarrow N_2(g) + NO_3(g)$ the activation energy ($E_a$) and overall $\Delta E$ are 154 and 136 kJ/mol, respectively. What is the activation energy for the reverse reaction? Express your answer in kilojoules per mole using two significant figures. $E_a$(reverse) = ? kJ/mol