Create the free-body diagram. Use the checkboxes to select...

Create the free-body diagram. Use the checkboxes to select the correct vectors as instructed above. Move the vectors to the correct starting points and orient them in the correct direction as instructed. mg fs FN T fk Key to Force Labels mg = Gravitational force fs = Static friction FN = Normal force T = Tension fk = Kinetic friction Draw free-body diagram here Point the acceleration vector in the correct direction

Transcript

00:01 Hello students, in this question we are given that a large lamp hangs vertically in a desaleredating elevator and we have to calculate the mass of the length and we are given the deacceleration value of the elevator that is equal to 2 .40 meter per second square and initially we are given that the elevator is moving downward direction with a deacceleration equal to 2 .0 2 .4 meter per second square and initially we are given that the elevator is moving downward direction with the acceleration equal to 2 .0 2 .4 meter to.

00:30 For seconds where and we are given that the tension in the string of the row is equal to 89 .0 so for example if we try to draw the fbd we are given this block which we denote which denotes our lamp and we are given that mg that is forced due to gravity acts in the downward direction and tension on the lamp adds in the upward direction and as we are given that the the elevator is moving downward but with a d acceleration so a net acceleration would be acting in upward direction that would be equal to 2 .40 meters per centrist.

01:11 So this is the value of d acceleration.

01:14 We are denoting that by a, that is a.

01:19 We are denoting are the mass mass of lemm by letter m and the tension is denoted by letter p.

01:31 So, first of all, using loss of motion, using laws of motion, which means that f -net on any object is equal to mass multiplied by the oscillate.

01:48 And for the lamp, the f -net on the lamp would be equal to tension minus the force due to gravity, that is, m -g.

01:59 So, putting the value of f -net in the first equation, that is, f -net is equal to mass -tens acceleration.

02:08 So we can see that t -minus m -g is equal to mass -times acceleration...

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