00:02
Hey there, in this question we are given an unbalanced chemical equation.
00:06
So the first thing we need to do is balance that.
00:13
Unbalanced equations are simply offensive.
00:16
We need to make sure when we write an equation it's balanced.
00:19
And in fact in this question we need to use that balanced equation.
00:23
So that makes it all the more important.
00:26
All right so to balance we need to add coefficients.
00:29
We see there's one carbon on the left and one carbon on the right.
00:32
So we don't need to add any coefficients to make those equal.
00:35
Next let's look at the sulfur.
00:36
There are two on the left but only one on the right.
00:38
So i need a coefficient of two in front of so2 to give me two sulfur on each side.
00:44
Now as we look on the right side we see that we have two oxygen plus we have two times two for four more for a total of six oxygen on the right.
00:53
That means we need to add a three in front of o2 on the left to give us a balanced chemical equation.
01:01
This is now balanced with one carbon on each side, two sulfur on each side, and six oxygen.
01:07
Okay so this balanced equation tells us the ratio in which the reactants react and the products are formed.
01:14
So if we were to interpret this it tells us that one molecule of cs2 reacts for every three molecules of o2.
01:24
And i got those numbers simply from the coefficients.
01:27
Since there's no coefficient in front of cs2 we know it's a one.
01:31
And we see that three there in front of the o2.
01:34
This then is going to produce one molecule of co2...