Cu + 2 AgNO3 → Cu(NO3)2 + 2 Ag When 50.0 g of copper was reacted with 300.0 g of silver nitrate solution, 149 g of silver was obtained. What is the percent yield of silver obtained?
Added by Raymond G.
Step 1
The balanced chemical equation tells us that one mole of copper reacts with two moles of silver nitrate to produce two moles of silver. The molar mass of copper (Cu) is approximately 63.55 g/mol. So, 50.0 g of copper is approximately 50.0 g / 63.55 g/mol = Show more…
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