We want to find the time when the charge is 10% of the initial charge, so we can set up the equation:
$$0.1Q_0 = Q_0 e^{-t/RC}$$
Divide both sides by $Q_0$:
$$0.1 = e^{-t/RC}$$
Now take the natural logarithm of both sides:
$$\ln(0.1) = -t/RC$$
Solve for
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