00:01
Hi, here in this given problem, mass of the luge along with the rider.
00:18
This is given as m is equal to 85 kilogram.
00:24
Retardation in the motion that is 2 .0 meter per second square.
00:36
His initial speed, vi, that is 37 meter per second, and it is coming to rest, coming to stop.
00:44
So vf will be equal to 0.
00:46
In the first part of the problem, we have to find force being applied on it, resistive force.
00:52
So using newton's second of motion, f is equal to m .a means that will be 85 into a2.
01:02
So this force comes out to be equal to 170 newton.
01:07
Answer for the first part of the problem.
01:10
Then in the second, second part of the problem, we have to find total distance covered before coming to rest.
01:19
For which we will use third equation of motion, vf square is equal to vi square plus 2a into d...