00:03
We are given the chemical equation and copying down.
00:11
Started with the problem as soon as i'm done getting this down.
00:23
Okay.
00:24
We're asked to find the theoretical yield of silver metal in grams.
00:42
Given.
00:49
And then we are given 1 .50 grams of copper wire.
00:56
And we are given 75 .00 milliliters of silver nitrate.
01:08
I'm going to start with this one so i can get the rest of my given down here.
01:14
And we're told that this is 0 .750 molar silver nitrate.
01:30
Okay, so what we're going to do here is find our theoretical yield.
01:36
What is the actual yield if the percent yield is? okay.
01:40
So our first step is to find our limiting reactant and our theoretical yield.
01:47
Let me be t.
01:50
I think it's 63 .55.
01:53
It is indeed.
01:53
63 .55 grams per mole is the atomic mass of copper.
02:02
I have a one, did i forget to balance this? i did indeed.
02:11
A one to two mole ratio for copper to silver.
02:18
And my molar mass of silver is 107 .87.
02:38
So if copper were my limiting reactant, which we won't know until i do my next calculation, let me check.
02:52
I have 1 .5 times 2 times 107 .87 divided by 63 .55.
02:58
This equals 5 .09 grams of silver could be produced.
03:12
Now next, i'm going to finish this one by using a one to, excuse me, a two to two mole ratio of silver to silver nitrate.
03:27
Then i really hate doing this.
03:29
I have, maybe i'll just stop here...