00:01
In this question we are given that from the given data we have our value for lambda which is given us as 1 .3 per millimeter.
00:13
So therefore our probability for getting x is equal to x our formula is e to the power of minus lambda, lambda 3 to the power of x divided by factorial x.
00:27
So we will use this formula to solve our values in the given part.
00:32
Part a are expected number of customers in 1 r will be equal to 1 upon 3 multiplied by 60 will be equal to 20 customer per so here we have our answer for part a that in a r total number of customers will be 20 and this is our fourth solution of this question.
01:21
This is our first.
01:23
Now in part b, we need to find the main number, number of customer in 9 minutes.
01:42
So this will be calculated as from lambda is equal to 1 upon 3 multiplied by 9, which is equal to 3 2 customer will be stated as probability of getting x is equal to 2 is equal to e to the power of lambda and lambda is here as we have find it 3 so minus 3 and then multiplied by 3 to the power of x which is 2 divided by factorial 2 so when we calculate our value will be equal to 0 .2 to 40.
02:32
So here we have our probability for getting exactly two customers.
02:37
So this is the answer for part b.
02:43
Answer of part b...