Question

196. A 6am, the temperature was -11°C. The temperature increased at a constant rate of 3.2°Cper hour. What expression represents the temperature at 12 noon? A) -11+9.2 B) -11+7(3.2) C) -11-19.2 D) -11+3.2×6 E) none of the above

          196. A 6am, the temperature was -11°C. The temperature increased at a
constant rate of 3.2°Cper hour. What expression represents the
temperature at 12 noon?
A) -11+9.2
B) -11+7(3.2)
C) -11-19.2
D) -11+3.2×6
E) none of the above

Added by Lacey J.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Jerelyn Nevil

03/02/2024

Step 1

The time elapsed from 6 am to 12 noon is 6 hours. Temperature increase per hour = 3.2°C Total increase in temperature = 3.2°C/hour x 6 hours = 19.2°C Show more…

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D) 65,417 E) none of the above At 6 am, the temperature was -11°C. The temperature increased at a constant rate of 3.2°C per hour. What expression represents the temperature at 12 noon? A) -11 + 9.2 B) -11 + 7(3.2) C) -11 - 19.2 D) -11 + 3.2 x 6 E) none of the above 2:11 AM Thu 4 Apr 19% udst_amp_study_guide-mi... Design alternatives control... ch02 gJI_ogaJI_aWJI_ClWs1 Notes on 09/02/2024 Math placement t... 88 D) 65,417 E) none of the above At 6 am, the temperature was -11°C. The temperature increased at a constant rate of 3.2°C per hour. What expression represents the temperature at 12 noon? A) -11 + 9.2 B) -11 + 7(3.2) C) -11 - 19.2 D) -11 + 3.2 x 6 E) none of the above