3-27 A 30-hp pump motor is used for an average of 8 h/day. If the motor has an efficiency of 88%, what would be the cost of operating the motor over a 20-day period if the industrial rate is 6 cents/kW \cdot h?
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The power of the motor is given as 30 hp. To convert this to watts, we multiply by the conversion factor of 746 watts/hp. 30 hp * 746 watts/hp = 22,380 watts The motor is used for 8 hours per day, so the energy consumption per day is: 22,380 watts * 8 hours = Show more…
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