The initial velocity of \( m_1 \) is \( 25.00 \, \text{m/s} \) at an angle of \( 150^\circ \).
- \( v_{1x} = 25.00 \cos(150^\circ) \)
- \( v_{1y} = 25.00 \sin(150^\circ) \)
Calculate:
- \( v_{1x} = 25.00 \times (-\frac{\sqrt{3}}{2}) = -21.65 \, \text{m/s} \)
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