00:01
Hi, here in this given problem that magnitude of magnetic field which is directed into the page that is 0 .14 tesla, then time taken by the loop to come out of the uniform magnetic field completely that will be given by 0 .3 second minus 0 .1 second means this is 0 .2 second and distance moved within this duration of time that is equal to half of the length of the loop which comes out to be equal to 0 .375 meter.
01:07
So, speed of the loop towards right that will be given by distance divided by time means this is 0 .375 meter divided by 0 .2 second and it is calculated to be equal to 1 .875 meter per second speed of the left arm of the loop within this magnetic field.
01:33
So, emf induced will be given by the expression bvl, b 0 .14 tesla multiplied by v we have found it to be equal to 1 .875 multiplied by length of the left arm that is given as 0 .350.
01:52
So, this emf induced is calculated to be equal to 0 .092 volt which is the answer for the first part of this given problem here.
02:05
Then in the second part resistance of the loop that is given as 0 .05 ohm.
02:13
So, current induced in this loop using ohms law that will be given by emf induced divided by the resistance.
02:21
So, this is 0 .092 divided by 0 .05 and it comes out to be equal to 1 .84 ampere.
02:31
So, the current is 1 .84 ampere one of the answer for this second part of the problem and to find its direction the magnetic flux linked through this loop that will be reducing that is first of all inward and decreasing as the loop is moving towards right...