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\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}, \quad m = -\frac{d_i}{d_o} When a real object is placed 22 cm from a lens, it produces an upright image with a magnification of 0.8. What is the focal length of the lens in cm? Express the numeral of your answer, including sign, with 3 or more significant figures.

          \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}, \quad m = -\frac{d_i}{d_o}

When a real object is placed 22 cm from a lens, it produces an upright image with a magnification of 0.8. What is the focal length of the lens in cm? Express the numeral of your answer, including sign, with 3 or more significant figures.
        
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(1)/(f) = (1)/(do) + (1)/(di),   m = -(di)/(do)

When a real object is placed 22 cm from a lens, it produces an upright image with a magnification of 0.8. What is the focal length of the lens in cm? Express the numeral of your answer, including sign, with 3 or more significant figures.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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When a real object is placed 22 cm from a lens, it produces an upright image with a magnification of 0.8. What is the focal length of the lens in cm? Express the numerical answer, including sign, with 3 or more significant figures.
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Transcript

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00:01 So we have an object placed 10 centimeters away from a converging lens.
00:07 So this is 10 centimeters.
00:09 And we're told that this lens has a focal length of 30 centimeters.
00:12 So i probably didn't give myself the most room to draw the scale of this appropriately.
00:17 Let's say this is 10 centimeters.
00:19 And then three times this distances are focal length, so maybe right about here.
00:24 And we want to know what's the nature of this image, where is it produced, and things like that.
00:29 So this is 30.
00:32 So we have 1 over 10 plus 1 over the image distance is equal to 1 30th.
00:40 And so the image distance, if we saw for this, comes out to be negative 15 centimeters.
00:45 So it is to the left of the lens.
00:47 It's on the same side as the object...
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