d) Suppose that $f(x) = g(x^2 + 2)$, that $g'(1) = -1$, $g'(2) = -4$, $g'(3) = 2$ and $g'(4) = 4$. What is $f'(1)$?
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Since f(x) is defined as g(x^2 + 2), we can use the chain rule to find its derivative. Using the chain rule, we have: f'(x) = g'(x^2 + 2) * (2x) Now, we need to find f'(1). Plugging in x = 1 into the equation above, we get: f'(1) = g'(1^2 + 2) * (2 * 1) Since Show more…
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