Data Table 2: Build Circuit, Measure Current and...

Data Table 2: Build Circuit, Measure Current and Voltage. Following the instruction of Basic Operation to build above circuit, measure current I1 and voltage V1 for R1, and so on. Calculate Power P = I · V (W). To see direction of [current] check mark on Show Current/Convention. ?1 = 12 V, ?2 = 9 V. Attach a screenshot of R1, I1, and V1 Measurement from the Simulation to lab report. N (#) Rn (?) In (A) Vn (V) Pn (W) 1 (R1) 10 2 (R2) 11 3 (R3) 15 Question: Show work of theoretical calculation (show detailed Kirchhoff's rule equations) for I1, I2, and I3. Answers should be in 3 sf (significant figures).

Transcript

00:01 So let us start with the concept which we are going to use here for this question.

00:07 So since we know that if the two resistances were connected in parallel, then r equivalent will be equal to r1 into r2 divided by r1 plus r2 if two resistances were connected in series.

00:23 In that case, the resistance equivalent will be equal to r1 plus r2, while according to ohm's law v is equal to i into r.

00:32 So this concept we are going to use.

00:34 So first of all, let's have a look to the circuit.

00:36 So let's suppose this is nothing but the circuit in which you can see that emf is 18 volt, r1, r2 and r3 resistances are connected.

00:43 So first of all, let us calculate the r2, r3 equivalent resistance, which is connected in parallel to each other.

00:51 So this will be equal to by using formula r2 into r3 divided by r2 plus r3.

01:00 So that will be equal to 60 multiplied by 20 divided by 60 plus 20, which is comes out equal to 15 ohm's.

01:11 Now we can replace r2 and r3 by the equivalent resistance r2, r3 in the series with r1 and hence the required equivalent resistance for the whole circuit will become equal to r2, 3 plus r1.

01:27 So that will be equal to 15 plus 22 will comes out 37 ohm.

01:34 Now let us calculate the currents i1, i2 and i3.

01:37 So what is i1? so let's say i1 is the current flowing throughout this, i2 is the current flowing throughout the r2 and i3 is the current flowing throughout the r3.

01:46 So we need to calculate this i1, i2 and i3.

01:49 So by using the kirchhoff's voltage law, okay, let us apply the kirchhoff's voltage law.

01:56 So let's say this is first loop, this is nothing but the second loop.

02:00 So applying the kirchhoff's voltage law to the first loop in which it says that the sum of the voltage inside the closed loop is always equals to 0.

02:09 So according to this, it will be the emf e minus of i1 into r1 minus of i3 into r3, this should be equals to 0.

02:18 So let's substitute values 18 minus of 22 of i1 minus of 20 of i3 would be equals to 0.

02:26 Let's say this as equation number first.

02:28 Now using the same kirchhoff's voltage law in the second loop, we can write down the equation that is i2 into r2 minus of i3 into r3, this will be equals to 0.

02:43 So let's substitute the values that is 60 times of i2 minus of 20 times of i3 will be equals to 0...

Question

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