Question

Daye 15. In a class of 40 students, the no. of In a class of the fifths of the number of givels is thre soys. Find the of boys in the class. boys. Jatal students \( =40 \) No. of boys \( =x \) No. of giales \( =y \) No. of girls \( =\frac{3}{5} \) of no. of boys \[ \begin{array}{l} \Rightarrow x+y=40 \\ \Rightarrow x=40-y \end{array} \] Now, \( x=\frac{3}{5} \) of \( y \) \[ \begin{array}{l} \Rightarrow 40-y=\frac{3}{5} y \\ \Rightarrow 40-\frac{3}{5} y+y \\ \text { (2) } 40=\frac{3 y+5 y}{5} \\ \text { ?? } \Rightarrow 40 \times 5=8 y \\ \Rightarrow 400 \times 5 * 40 \times 5=8 y \\ \begin{array}{l} \Rightarrow 200=8 y \\ \Rightarrow \frac{200^{25}}{8}=y \quad \Rightarrow y=25 \mathrm{ct} \end{array} \end{array} \]

          Daye
15. In a class of 40 students, the no. of In a class of the fifths of the number of
givels is thre soys. Find the of boys in the class.
boys.

Jatal students \( =40 \)
No. of boys \( =x \)
No. of giales \( =y \)
No. of girls \( =\frac{3}{5} \) of no. of boys
\[
\begin{array}{l}
\Rightarrow x+y=40 \\
\Rightarrow x=40-y
\end{array}
\]

Now, \( x=\frac{3}{5} \) of \( y \)
\[
\begin{array}{l}
\Rightarrow 40-y=\frac{3}{5} y \\
\Rightarrow 40-\frac{3}{5} y+y \\
\text { (2) } 40=\frac{3 y+5 y}{5} \\
\text { ?? } \Rightarrow 40 \times 5=8 y \\
\Rightarrow 400 \times 5 * 40 \times 5=8 y \\
\begin{array}{l}
\Rightarrow 200=8 y \\
\Rightarrow \frac{200^{25}}{8}=y \quad \Rightarrow y=25 \mathrm{ct}
\end{array}
\end{array}
\]

Daye
15. In a class of 40 students, the no. of In a class of the fifths of the number of
givels is thre soys. Find the of boys in the class.
boys.

Jatal students =40
No. of boys =x
No. of giales =y
No. of girls =(3)/(5) of no. of boys

⇒ x+y=40
⇒ x=40-y

Now, x=(3)/(5) of y

⇒ 40-y=(3)/(5) y
⇒ 40-(3)/(5) y+y
(2) 40=(3 y+5 y)/(5)
?? ⇒ 40 × 5=8 y
⇒ 400 × 5 * 40 × 5=8 y

⇒ 200=8 y
⇒(200^25)/(8)=y ⇒ y=25 ct

Added by Joshua M.

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