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Hello students, let's look at a question.
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This question has parts.
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The first one is when ch3, c -o -c -l, it reacts with k -f.
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Then the product would be here, when k -f is split, positive charge on k and negative charge on f.
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Then the product would be ch -3 -c -o -f.
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K -c -c -l will remove doubt in this.
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Reaction and f replaced cl chlorine.
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Next part is b part is when this compound this is react with h2o water.
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Here removal of in the presence of hcl and in this reaction there is removal of there is sorry not removal here this reaction takes place like this this is the product here what happened this h2o this splits into h and o h and one h is attached with the n h group and o h attached with the other one next part of this reaction is all of this question is c part is when benjoic acid this is banjoic acid here functional group is c o h that is carboxylic acid and this carboxylic acid is attached to benji rings so it is called banjoic acid it react with s -o -c -l -2 and ch3 and h -2 they react to form this is bane ring they react to form c double bond o and h c h c -h c -h -c -3 this is the product of this reaction d part of this question is d part of this question is when here this is the react this is reactant when this reactant react with when they these two reactant react with each other the here the product would be this edge this is additional reaction we can see this is here the product is formed by the addition of these two product these two reactants so here this is the product next part of this question is e part is when this is the product this is benzine ring and on benzine ring two oh group is attached one is here which is alcohol this is the alcohol functional group and when this react with the cocl2 then here the product would be here removal of hcl occur this is the product this is benzine this is oxygen and here removal of hcl occur in this reaction plus hcl...