00:01
The first lewis structure is p, f, 4 minus, to know whether or not what they've drawn is plausible.
00:09
Let's count the number of valence electrons.
00:12
Phosphorus has five.
00:14
Fluorine has seven.
00:15
There are four of them.
00:16
Plus there's one more due to the minus charge.
00:20
So if we take five plus seven times four plus one, we get a total of 34 valence electrons.
00:30
So if we take and put phosphorus in the middle and we bond all four fluorines to the phosphorus, and then give each fluorine three lone pairs so that each fluorine has an octet, we would have used up a total of 8 times 4 or 32 valence electrons.
00:56
That gives us two more that we can add as a lone pair to phosphorus.
01:05
Phosphorus is found in period 3, so it does have de -orbital and can have an expanded octet.
01:14
So what i have written here is a plausible lewis structure, and that is the exact lewis structure that is given for the ion.
01:25
So the answer is yes.
01:28
This is a reasonable lewis structure.
01:33
For the next one, we have o3.
01:38
Oxygen has six valence electrons.
01:40
There are three of them.
01:42
So that gives us a total of 18.
01:44
If we put all three oxygens in line bonding each one to each other and give the peripheral oxygens, three lone pairs, then we would have used up eight times two.
01:59
That's 16.
02:00
We have two more remaining that we can put on the central oxygen, but that doesn't give the central oxygen an octet.
02:07
So one of these oxygens, needs to share one of its lone pairs and form a double bond...