00:01
The first lewis structure that they'd given us is for s -f3 minus.
00:09
There are six valence electrons on sulfur, seven on fluorine.
00:13
There are three of them, plus one more with the minus charge, gives us a total of 28 valence electrons.
00:21
So if we put sulfur in the middle and we bond the fluorines, and we give two of the fluorines an octet with the, three loan pairs and then make a double bond and then give fluorine more than an octet down here.
00:46
We would have used up a total of two, four, six, eight, ten, twelve, fourteen, sixteen, eighteen, twenty, two, four, six, eight.
00:57
So we have the appropriate number of valence electrons, but what is wrong is this, fluorine cannot have an expanded octet.
01:06
And the way it is, it has 2, 4, 6, 8, 10 electrons assigned to it.
01:13
So the answer is no.
01:15
The total number of valence electrons are correct, but some atoms have the wrong number of electrons around them.
01:24
The symbols of the problem are f.
01:30
F has an issue.
01:33
Then for the next one, we've got al, cl3.
01:45
Aluminum has three valence electrons.
01:49
Chlorine has seven.
01:51
There are three of them.
01:53
That gives us a total of 24 valence electrons.
01:59
In the structure we have al with three chlorines bonded to it...