00:01
The correct lewis structure for aluminum trichloride can be determined by first calculating the total number of valence electrons.
00:11
Aluminum has three valence electrons, and chlorine has seven.
00:19
There are three of them.
00:20
That gives us 24 total valence electrons.
00:26
So if we bond the chlorines to the aluminum, we would have used up six, two electrons per bond.
00:38
And if we give each chlorine six more, then we would have used up all 24 valence electrons.
00:47
This is the correct lewis structure.
00:50
The one provided has an additional loan pair here.
00:54
So the answer is no.
01:00
The total number of valence electrons is wrong.
01:03
This has two more valence electrons than is available.
01:07
For the next one, we have of2.
01:15
Oxygen has six valence electrons.
01:17
Fluorine has seven, there are two of them.
01:20
So we have a total number of 20 valence electrons.
01:24
So if we put oxygen in the middle and we bond the fluorines to it, fluorines never have double bonds, so that lewis structure that's provided is incorrect.
01:35
We would have used up four, so we've got 16 left...