20. [20] Complete the function g only using if (without elif or else) so that its output is the same as f. 1 2 def f(a,b,c,x): 3 if a and not b: 4 return x + 1 5 elif b or c: 6 return x-1 7 else: 8 return x+10 10 11 def g(a, b, c,x): 12 #TO DO 13 i = [0,11 14 for a in i: 15 for b in i: 16 for c in i: 17 print (f(a,b,c, 1), " ", g(a,b,c,1)) Output 10 10 0 0 0 0 0 0 2 2 2 2 0 0 0 0
Added by Robert C.
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First, let's analyze the function `fa, b, c`: - The function takes three arguments: `a`, `b`, and `c`. - It starts with an `if` statement: `if a and not b`. - If `a` is `True` and `b` is `False`, it returns `x1`. - If the `if` condition is not met, it moves to Show more…
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The following code snippet: def func1(a): return None def func2(a): if a > 2: return func1(a) * func1(a) else: return func1(a * 4) print(func2(4)) a. Will output None. b. Will output 16. c. Will cause a runtime error. d. Will output 4.
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If $A\left[\begin{array}{rr}0 & 1 \\ 2 & -1\end{array}\right]=\left[\begin{array}{rr}2 & 1 \\ -1 & 0\end{array}\right]$ where $A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]$, then $A$ is (a) $\left[\begin{array}{ll}2 & 1 \\ 0 & 0\end{array}\right]$ (b) $\left[\begin{array}{rr}0 & 1 \\ 2 & -1\end{array}\right]$ (c) $\left[\begin{array}{rr}2 & 1 \\ -1 & 0\end{array}\right]$ (d) $\left[\begin{array}{cc}2 & 1 \\ -1 / 2 & -1 / 2\end{array}\right]$
Which will result error. (python)
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