Question

Define the suspension of a fan unit: \text{mass:} 200 kg Rotation frequency: 2 400 rpm Stiffness of supporting structure $5.10^6$ N/m a/ find the excitation frequency b/ explain and apply rule n°1 c/ explain and apply rule n°2 d/ define the suspension stiffness e/ comment the result

          Define the suspension of a fan unit:
\text{mass:} 200 kg
Rotation frequency: 2 400 rpm
Stiffness of supporting structure $5.10^6$ N/m
a/ find the excitation frequency
b/ explain and apply rule n°1
c/ explain and apply rule n°2
d/ define the suspension stiffness
e/ comment the result

Define the suspension of a fan unit:
mass: 200 kg
Rotation frequency: 2 400 rpm
Stiffness of supporting structure 5.10^6 N/m
a/ find the excitation frequency
b/ explain and apply rule n°1
c/ explain and apply rule n°2
d/ define the suspension stiffness
e/ comment the result

Added by Soledad M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Aparna Shakti

Step 1

1 rpm = 1/60 Hz So, the rotation frequency in Hz is: 2400 rpm * (1/60 Hz/rpm) = 40 Hz Show more…

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Define the suspension of a fan unit: Mass: 200 kg Rotation frequency: 2,400 rpm Stiffness of supporting structure: 5.10 N/m a/ Find the excitation frequency b/ Explain and apply rule 1 c/ Explain and apply rule 2 d/ Define the suspension stiffness e/ Comment on the result