00:01
Hi, in this question we have to derive an expression for electric field due to electric dipole at a point on its axial line.
00:10
So let a -b are the two dipoles.
00:20
So the charge will be minus q and plus q and the distance between these two will be twice of d.
00:28
So let p be the point here on this axial line where.
00:38
We have to calculate the electric field due to these two dipoles.
00:44
So the center of this dipole is at o and the electric field e1 is in this direction and electric field e2 is in this direction.
00:58
Now, electric field at the point p due to plus q dipole that is placed at b is e1.
01:11
And e1 will be equals to 1 upon 4 pi epsilon knot, q divided by r minus d square where r is the distance from the center to the point p.
01:29
So from here to point p, this distance is small r.
01:34
Now, the electric field at the point p, due to minus q charge that is placed at a, that is e2, will be 1 .4 pi epsilon knot, q by r plus d, square.
01:52
Now, the magnitude of the resultant electric field acts in the direction of the vector with a greater magnitude...