Describe how you would prepare 500ml of 0.2M acetate buffer(pH 5.4) given the following information: pKa for acetic acid is 4.76 specific gravity of acetic acid is 1.05, percentage purity ( acetic acid) 98%
Added by Sepati Z.
Step 1
2M solution. - The formula to calculate moles is Molarity (M) = moles of solute / liters of solution. - Therefore, moles = Molarity × liters = 0.2 M × 0.5 L = 0.1 moles. Show more…
Show all steps
Your feedback will help us improve your experience
Jennifer Hudspeth and 91 other Chemistry 102 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Preparation of Buffer of Known $\mathrm{pH}$ and Strength Given 0.10 M solutions of acetic acid $\left(\mathrm{p} K_{\mathrm{a}}=4.76\right)$ and sodium acetate, describe how you would go about preparing $1.0 \mathrm{L}$ of $0.10 \mathrm{M}$ acetate buffer of $\mathrm{pH} 4.00.$
Prepare 100 mL of a 0.2 M acetate buffer solution with a pH of 4.76 (using 17.6 N acetic acid and sodium acetate). a. Calculate the volume of acetic acid and the weight of sodium acetate necessary to prepare the buffer solution. The pKa of acetic acid is 4.76.
Imaan A.
Given 0.10 M solutions of acetic acid pKa=4.76 and sodium acetate, describe how would you prepare 1.0L of 0.10M acetate buffer of pH4.00. Please explain.
David C.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD