00:01
Let's discuss this question.
00:02
So here we need to calculate the equivalent capacitance between point a and v for each of the two networks shown in the figure.
00:10
So let's start.
00:12
Here we can say these capacitors are in series 1 divided by c effective that is equal to 1 divided by c plus 1 divided by c plus 1 divided by c.
00:33
So c effective will be equal to c divided by 3.
00:39
So here we can say, for example, this is a and here we have capacitance and here again we have a capacitance.
00:51
And here we have capacitance and this will be b.
00:57
This is c and further here, this will be c divided by 3.
01:05
So here we can say c effective here is equal to c plus c divided by 3 that will be equal to 4c divided by 3.
01:18
So further here we can say as we got 4c divided by 3 so 1 divided by c effective is equal to 1 divided by c plus 1 divided by c plus 3 divided by 4c.
01:33
So here we can say c effective is equal to 4c divided by 11 and c effective is equal to 2 .94 muf.
01:48
So here we can say therefore c equivalent is equal to 2 .94 muf and this is the value of equivalent capacitance.
02:04
Now solving for network 2.
02:09
Here we can say here capacitance are in series connection so 1 divided by c effective is equal to 1 divided by c plus 1 divided by c plus 1 divided by c so c effective is equal to c divided by 3...