00:01
In this question we have been given that the power is equal to 39 .75 kw, the speed is equal to 215 rpm and the service factor is equal to 1 .5.
00:29
So, to find the rated torque, the formula is torque rated equals to 39 .75, that means power times, because it's in kilo, so let us convert it in watt, 1000 times 60 divided by 2 pi of speed, that is 215.
01:12
This would be equal to 20 .8 knm.
01:23
Now to design the torque, so t design would be equal to t rated times the service factor.
01:38
So, this would be equal to 20 .8 times 1 .5 which would be equal to 31 .2 knm.
01:51
Now the suitable materials would be, for flange it would be steel, that's let's say aisi 1045, this kind of material.
02:32
For bolt, the material would be grid of steel 8 .8 and for the key, the material would be aisi of steel 4140.
02:54
Now to design the coupling, so assuming the shaft diameter to be 60, the formula for that would be t equals to 0 .1 times under root of t design times the diameter.
03:24
Okay, so t would be equal to 0 .1 times under root of the value of t design is 31200 times 60, so this will comes out to be 62 .8 mm.
03:48
Okay, now this is for the flange design...