Question

Determine a 90% confidence interval to estimate the population mean lenth of films produced in the last 10 years. While assuming the population is normally distributed and a sample of 20 films has an average length of 102 minutes. Additionally, the film lengths have a population standard deviation of 27 minutes.

          Determine a 90% confidence interval to estimate the population mean lenth of films produced in the last 10 years. While assuming the population is normally distributed and a sample of 20 films has an average length of 102 minutes. Additionally, the film lengths have a population standard deviation of 27 minutes.
        
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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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Determine a 90% confidence interval to estimate the population mean lenth of films produced in the last 10 years. While assuming the population is normally distributed and a sample of 20 films has an average length of 102 minutes. Additionally, the film lengths have a population standard deviation of 27 minutes.
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Transcript

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00:01 Okay, in this problem we have to find a 90 % confidence interval for the population mean.
00:06 Now, i don't have any specifics.
00:09 So what we need in order to do that is we need a sample size, right? i'm going to suppose maybe that the sample size is 30.
00:16 And then what we need is a sample mean.
00:19 So i'm going to suppose that my sample mean, and again i'm just making up these numbers, is going to be maybe 45 .3.
00:30 And then we also need a sample standard deviation.
00:33 And i'm going to say maybe that my standard deviation is 3 .1.
00:37 And then the last thing that we need is our z -score that's associated with 90%.
00:43 And that we can just look up online.
00:46 That is going to be 1 .645.
00:49 So our z -score for 90 % is going to equal 1 .645.
00:56 Let me double check making sure.
00:58 All we have to do is look up that on a table or look it up online.
01:02 And yeah, it's 1 .6449, which is 1 .645.
01:06 All right, so with this we can put it into our formula for a confidence interval.
01:10 And that's going to be x -bar plus or minus our z -score for 90 % times our standard deviation over the square root of our sample size.
01:21 All right, so whatever the numbers are that are in your problem, all you need to do is substitute these values in.
01:27 Now z for 90 is going to be 1 .645.
01:30 That's not something you have to make up or something you have to look for...
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