Question

CH 8050 Practice Set 3 S'24 1. Determine all of the vibrational modes of PF$_5$ in the trigonal bipyramidal geometry (D$_{3h}$). 2. Determine all of the vibrational modes of Fe(CO)$_5$ in the trigonal bipyramidal geometry (D$_{3h}$).

          CH 8050 Practice Set 3 S'24
1. Determine all of the vibrational modes of PF$_5$ in the trigonal bipyramidal geometry (D$_{3h}$).
2. Determine all of the vibrational modes of Fe(CO)$_5$ in the trigonal bipyramidal geometry (D$_{3h}$).
        
Show more…
CH 8050 Practice Set 3 S'24
1. Determine all of the vibrational modes of PF5 in the trigonal bipyramidal geometry (D3h).
2. Determine all of the vibrational modes of Fe(CO)5 in the trigonal bipyramidal geometry (D3h).

Added by Luz S.

Close

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Determine all of the vibrational modes of PF_(5) in the trigonal bipyramidal geometry (D_(3h)). Determine all of the vibrational modes of Fe(CO)_(5) in the trigonal bipyramidal geometry (D_(3h)). CH 8050 Practice Set 3 S'24 1.Determine all of the vibrational modes of PFs in the trigonal bipyramidal geometry (Dan 2.Determine all of the vibrational modes of Fe(COs in the trigonal bipyramidal geometry (Dan)
Close icon
Play audio
Feedback
Powered by NumerAI
David Collins Jennifer Stoner
Kathleen Carty verified

Vaidik Stats and 95 other subject Chemistry 101 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
predict-the-molecular-geometries-of-all-the-following-compounds-using-vsepr-a-sfs-b-i-c-sef-d-sfz-e-pfs-linear-bent-trigonal-planar-tetrahedral-trigonal-pyramidal-trigonal-bipyramidal-octahe-40366

Predict the molecular geometries of all the following compounds using VSEPR: a) SF6 b) I3- c) SeF4 d) [SF3]- e) PF5 linear bent trigonal planar tetrahedral trigonal pyramidal trigonal bipyramidal octahedral square planar T-shape seesaw square pyramidal

Vaidik S.

using-vsepr-theory-determine-the-electron-group-geometry-and-molecular-shape-of-the-substances-shown-ofz-shape-linear-electron-geometry-tetrahedral-molecular-hzco-c-is-central-electron-geome-85612

Using VSEPR theory, determine the electron-group geometry and molecular shape of the substances shown: OF2: Shape: linear Electron Geometry: tetrahedral Molecular Geometry: bent HzCO (C is central): Electron Geometry: trigonal planar Molecular Geometry: trigonal planar CF2Cl: Electron Geometry: tetrahedral Molecular Geometry: tetrahedral PCl2F: Electron Geometry: trigonal bipyramidal Molecular Geometry: seesaw

Adi S.

be-sure-t0-answer-all-parts_-predict-the-geometry-of-the-following-molecules-and-ion-using-the-vsepr-model-enter-the-number-corresponding-to-the-correct-geometry-in-the-box-next-t0-the-formu-81653

Predict the geometry of the following molecules and ion using the VSEPR model. Enter the number corresponding to the correct geometry in the box next to the formula. Electron Domain Molecular (a) CH3I (b) ClF3 (c) H2S (d) SO3 (e) SO4^2- 1 - bent 2 - linear 3 - octahedral 4 - seesaw-shaped 5 - square planar 6 - square pyramidal 7 - tetrahedral 8 - trigonal bipyramidal 9 - trigonal planar 10 - trigonal pyramidal 11 - T-shaped

Susan H.


*

Recommended Textbooks

-
Chemistry: Structure and Properties

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition
achievement 1,129 solutions
Chemistry The Central Science

Chemistry The Central Science

Theodore L. Brown 14th Edition
achievement 1,377 solutions
Chemistry

Chemistry

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste 10th Edition
achievement 1,903 solutions

*

Transcript

-
00:01 The first option which we have is sf6.
00:04 So, sf6 in this sulfur, it belongs to oxygen family.
00:09 Oxygen family.
00:10 That means it has 6 valence electron.
00:13 Since it has 6 valence electron and all the 6 valent electron are used up in bonding with fluorine, so bond pair is equal to 6, lowen pair is equal to 0.
00:21 And therefore, if we see the static number, it is 6 plus 0.
00:24 That means bone pair plus loan pair, it is equal to 6.
00:26 And when we have static number, we can comment on the hybridization.
00:29 So it is going to be sp3d2 and sp3d2 means what geometry it is going to be octahedral geometry octahedral geometry so the structure for this is sulfur will be present then fluorine chlorine and four other fluorines so this is basically the structure for sf6 moving forward we have is i3 minus in the case of i3 minus it is going to have a linear geometry linear geometry because in this case what happens over here idine means what belonging to halogen family means seven valence electron out of the seven valence electron the two valence electron are used up in bonding with another two atoms of idine so two used up therefore i can say bonding pair is equal to two and therefore we have loan pair how many we have to calculate because after removing two valence electron five is there but there is a negative charge means extra electron is there therefore six electrons are there since there are six electrons therefore it has three loan pairs so now the steyic number bond pair plus loan pair so 3 plus 2 is equal to 5 and hybridization would be sp 3d and the structure for this is i then we will have i negative then near this will have loan pairs in this fashion so these are the loan pairs which are present and it has a linear geometry for this next molecule which we have is s e f4 selenium tetrafluoride in this case this has a see -saw geometry.
02:08 Seesaw geometry.
02:11 Why? because when we consider the atom which we have is ses, s -e belongs to oxygen family.
02:17 So oxygen family means what? six -valence electron.
02:20 And since it has six -valence electron, out of the six -four used for bonding.
02:23 So bond pair is equal to four.
02:25 And loan pair is equal to how much? so loan pair is equal to one...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever