Determine how much iron (II) sulfide is produced when 9.42 g of iron reacts with sulfur according to the following reaction: Fe(s) + S(s) FeS(s) (1 mol FeS = 87.910 g)
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Step 1
Given: Mass of iron = 9.42 g Molar mass of iron = 55.84 g/mol Number of moles of iron = Mass of iron / Molar mass of iron Number of moles of iron = 9.42 g / 55.84 g/mol Number of moles of iron ≈ 0.169 mol Show more…
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