00:01
To answer this question, we do need the kb value for ammonia and the ka value for ammonium.
00:08
We are given the kb value.
00:10
The kb value for ammonia is 1 .76 times 10 to the negative 5.
00:21
So that means the ka value for ammonium will be that divided into kw or 5 .68 times 10 to the negative 5.
00:36
The negative 10 and then we have a k a value for hf which is 6 .8 times 10 to the negative 4 which means kb for f minus is going to be that value divided into kw which is 1 .47 times 10 to the negative 11.
01:11
Okay so the first compound is f f .e.
01:19
N .3, two of them.
01:23
Nitrate is found with a strong acid, nitric acid.
01:27
So nitrate, being its conjugate base, is a very, very weak base, weaker than water, to the point that we can ignore it.
01:36
But typically, highly protonated cation, such as fe3 plus, will behave as an acid, making the solution acidic.
01:49
Then for the next compound, we have cetion, c2, h5, and h3, br.
02:01
Br being found with a strong acid, hydrobromic acid, is the conjugate base to hydrobromic acid, and the conjugate base to any strong acid is so weak, it's weaker than water, we can ignore it.
02:18
But this is the diethyl ammonium ion, diethylamine is a weak base, so this is a weak acid, making the solution acidic.
02:37
The next one is lithium nitrite...