00:01
Hi, let's start the solution.
00:02
In this question, we have given matrix a is 1, minus 2, 3, minus 3, 5, 4, 2, minus 1, 2 and b equal to b1, b2, b3.
00:20
So to solve this question, first write the augmented matrix, so that is a augmented b.
00:36
So we get here augmented matrix a is 1, minus 2, 3, minus 3, 5, 4, 2, minus 1, 2 and b is b1, b2, b3.
00:54
Now reduce this augmented matrix in a row echelon form.
00:59
Apply row operation r2 is r2 plus 2 times r1 and r3 is r3 minus 3 r1.
01:10
So we get here first row as it is 1, minus 3, 2, b1, r2 plus 2 r1 means minus 2 2 2's are 4 minus 1 plus 4 is 3 and this one is b2 plus 2 b1.
01:38
Now apply operation in a third row that is r3 is r3 minus 3 r1 means 3 minus 3 is 0, 4 minus minus become positive 3 is a 9, 9 plus 4 is 13 and this one is 2 minus 6 that is minus 4 this one is b3 minus 3 b1.
02:04
Now again apply row operation r3 is r3 plus 13 times r2.
02:15
So we get first row as it is that is 1, minus 3, 2, b1 and second row that is 0, minus 1, 3 this one is b2 plus 2 b1 and that is 0, 13 minus 13 is 0, minus 4 plus 3 into 13 is 35.
02:38
This one is b3 minus 3 b1 plus 13 b2 plus 26 b1...