Question

Determine initial and final values of function x(t) if its Laplace transform is given by: \(X(s) = \frac{4s^2 + 28s + 40}{s(s + 3)(s + 4)}\)

          Determine initial and final values of function x(t) if its Laplace transform is given by:
\(X(s) = \frac{4s^2 + 28s + 40}{s(s + 3)(s + 4)}\)

Determine initial and final values of function x(t) if its Laplace transform is given by:
X(s) = (4s^2 + 28s + 40)/(s(s + 3)(s + 4))

Added by Sarah F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Hubert Agamasu

Step 1

The denominator of the Laplace transform is given by s(s + 3)(s + 4). To find the roots, we set the denominator equal to zero and solve for s: s(s + 3)(s + 4) = 0 This equation has three roots: s = 0, s = -3, and s = -4. Show more…

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