Question

Determine la corriente tat de un Shac en serie cuando: \[ \begin{array}{l} L=0,1 h \\ h=2 r \\ C: 0,1 f \\ \operatorname{con} i(0)=0 \\ E(t)=120 t-120 t u(t-1) \\ L \frac{d i}{d t}+\text { hi }(t)+\frac{1}{C} \int_{0}^{t} 1(\tau) d t=\tau(t) \end{array} \]

          Determine la corriente tat de un Shac en serie cuando:
\[
\begin{array}{l}
L=0,1 h \\
h=2 r \\
C: 0,1 f \\
\operatorname{con} i(0)=0 \\
E(t)=120 t-120 t u(t-1) \\
L \frac{d i}{d t}+\text { hi }(t)+\frac{1}{C} \int_{0}^{t} 1(\tau) d t=\tau(t)
\end{array}
\]

Determine la corriente tat de un Shac en serie cuando:

L=0,1 h

h=2 r

C: 0,1 f
con i(0)=0

E(t)=120 t-120 t u(t-1)

L (d i)/(d t)+ hi (t)+(1)/(C)∫0^t 1(τ) d t=τ(t)

Added by Zulek K.

Calculus: Early Transcendental Functions

Robert T. Smith, Roland B. Minton 3rd Edition

Chapter 15

Instant Answer

Solved by Expert Keondre Parker

Step 1

Given: \[ L = 0.1 \, \text{H} \] \[ h = 2r \] \[ C = 0.1 \, \text{F} \] \[ i(0) = 0 \] \[ E(t) = 120t - 120t \, u(t-1) \] The differential equation is: \[ L \frac{d i}{d t} + h i(t) + \frac{1}{C} \int_{0}^{t} i(\tau) \, d\tau = E(t) \] Show more…

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