00:01
In this problem we should determine the area under the standard normal curve that lies to the right of the z score value.
00:10
Task a, z equals minus 1 .78.
00:18
Let's mark on the graph, minus 1 .78.
00:27
Add a vertical line and sketch the area to the right side.
00:39
Needed area can be found by the following p z is greater than minus 1 .78.
00:51
This equals 1 minus p that is less than minus 1 .78.
01:02
And by using that score table, we can find the needed value of probability, 1 minus 0 .0375 and the final value is 0 .9625.
01:28
So this is the answer for the part a.
01:32
Let's mark on the graph.
01:33
The needed area is 0 .9625.
01:41
The next task, task b, that equals 0 .83.
01:52
So let's mark on the graph 0 .83.
02:00
Add a vertical line and sketch the area to the right.
02:07
The needed area will be p that is greater than 0 .83.
02:15
This equals 1 minus p that is less than 0 .83.
02:18
This equals 1 minus p that is less than 0 .8...